Russ P. answered 11/25/14
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Ivy,
Let p = probability of winning each time you play the game = 0.30
(1-p) = probability of losing each time you play the game = 0.70
W = $ you get when you win a game (the unknown)
L = $ you pay when you lose a game ($ 1.00 )
N = Number of times the game is played (large number, say over 100, to get a tight estimate (small std. deviation)
around the computed mean.
To be considered fair, your mean gains from games won must balance your mean losses from games lost, when N games are played.
Mean or average gain over N plays = pWN
Mean or average loss over N plays = (1-p)LN
Balancing these two, gives the solution W = (1 - p) L/p = 0.70 ($1.00)/0.30 = $2.33 as the N's cancel out.
Because a win is rarer than a loss, its payout has to be greater to make the game fair.
Ivy C.
11/25/14