Cara Marie M. answered 03/29/19
PhD in Biochemistry with 10+ Years of Teaching Experience
Hey there, we need to use the Henderson-Hasselbach equation for bases:
pOH = pKb + log (B-H+/B)
In this case, the B-H+ is the protonated base (NH4+) and the Base (B) is NH3. We can look up the pKb of NH3 (4.75).
pOH = 4.75 + log (0.4/0.2) = 5.05
pH = 14 - pOH = 14 - 5.05 = 8.95