
Drew B. answered 03/25/19
Patient and Experienced Ive League Chemistry Tutor
Hi Berryl,
Let's review some basic ideas:
Use the ideal gas law (PV = nRT) when you are asked about a property of a gas (pressure, volume, temperature, amount of moles) and you know three of those properties.
Mole fraction is the fraction of the total moles that a particular substance is contributing to that total:
mole fraction = moles substance / total moles
Think of partial pressure as the pressure a gas would exert if it was the only gas there. Partial pressure is proportional to the number of moles so: partial pressure = total pressure x mole fraction.
Let's calculate total pressure first.
We know the volume in liters and the temperature. We can also find the number of moles of each gas by conversion. So this is a good question for the ideal gas law. Make sure that your units match the idea gas constant, R.
V = 12.5 liters; T = 298 Kelvin; let's use R = 0.0821 L atm / mol K.
Now we want the total moles in the container.
Convert grams to moles by taking grams and dividing by molar mass:
24.2 grams Neon * 1 mol Neon / 20.18 g Neon = 1.199 mol Neon
4.32 grams Oxygen * 1 mol Oxygen / 31.998 g O2 = 0.135 mol Oxygen
Total moles equals the sum of those: 1.334 mol gas
Note that we can combine the moles of gas because according to ideal gas behavior, all ideal gases behave the same way regardless of chemical identity.
Solving for P:
P = nRT/V = 1.334*0.0821*298/12.5 = 2.611 atm.
Moles fractions:
Apply the equation given above: moles Neon/ divided by total moles = 1.199 mol/1.334 mol = 0.899
Oxygen: 0.135/1.334 = .101
Note that the mole fractions should add up to 1.
Partial pressures:
Apply the equation given above:
PNe = mole fractionNe * Ptot = 0.899 * 2.611 atm = 2.35 atm
PO2 = mole fraction * Ptot = 0.101*2.611 atm = 0.264 atm
Just like the mole fractions, the partial pressures should add up to the total pressure.
Hope that helps! You should run through the calculations on your own to be sure you understand.