Lauren H. answered • 03/24/19
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7 years experience teaching High School Chemistry and Honors Chemistry
Br2(g) + Cl2(g) → 2 BrCl(g)
If 5.790 g Br2 is mixed with 12.83 g Cl2
Repeat process as previously explained:
Beginning with each reactant amount in grams, convert to moles of reactant using molar mass. Insert mole ratio from balanced equation with moles of product as numerator and moles of reactant as denominator.
The answer that is LEAST will indicate the limiting reactant. The other reactant is the excess reactant.
Calculate the theoretical yield of product in grams by insetting a final molar mass term for the product.
Lauren H.
Ugh. OK. One more: 5.790g Br2 x (1 mol Br2/159.81 g Br2) x (2 mol BrCl/1 mol Br2) = 0.07 mol BrCl 12.83g Cl2 x (1 mol Cl2/70.90g Cl2) x (2 mol BrCl/1 mol Cl2) = 0.36 mol BrCl Br2 is the LR. 5.790g Br2 x (1 mol Br2/159.81 g Br2) x (2 mol BrCl/1 mol Br2) x (115.36 g BrCl/1 mol BrCl) = 8.36 g BrCl this is the theoretical yield.
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03/25/19
Abigail R.
tried it and still not getting the correct answer03/24/19