NH3 + H2O --> NH4+ + OH-
pOH = pKb + log [acid]/[base]
[OH-] = 1.0 × 10-5 M, pOH = 5
Kb = 1.8 × 10-5, pKb = 4.74
[ acid ] = [ NH4+ ], [ base ] = [ NH3 ] = 0.200M
5 = 4.74 + log [NH4+]/(0.2)
[ NH4+ ] = 0.364M
NH4NO3 --> NH4+ + NO3-
[ NH4NO3 ] = [ NH4+ ] = 0.364M concentration required