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Question

What volume of a 6.0M solution of NaOH would be required to neutralize 135.0mL of a 0.50M solution of HCI?

Answer 1

Balanced Reaction: NaOH + HCl → NaCl + H₂O

Calculate moles of HCl using its volume and molarity

mol HCl = 0.50 mol/L x 135.0 mL x (1 L / 1000 mL) = 0.0675 mol HCl

Since 1 mol of HCl reacts with 1 mol of NaOH,

mol NaOH = 0.0675 mol HCl x (1 mol NaOH / 1 mol HCl) = 0.0675 mol NaOH

Use moles NaOH and molarity to calculate volume.

Volume NaOH = moles / Molarity = 0.0675 mol / 6.0 mol/L = 0.01125 L x (1000 mL / 1 L) = 11 mL (rounded to 2 significant figures)