Ishwar S. answered 03/21/19
University Professor - General and Organic Chemistry
To determine the limiting reagent, convert grams of each reactant to moles of CO2. The reactant that produces less CO2 is the limiting reagent.
15.51 g C x (1 mol C / 12.01 g C) x (1 mol CO2 / 1 mol C) = 1.291 mol CO2
15.18 g O2 x (1 mol O2 / 32.00 g O2) x (1 mol CO2 / 1 mol O2) = 0.4744 mol CO2
From above, you can see that O2 produces less CO2, therefore, it is the limiting reagent. Theoretical yield of CO2 is
0.4744 mol CO2 x (44.01 g CO2 / 1 mol CO2) = 20.88 g CO2