Arthur D. answered 11/18/14
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distance=rate*time
d=r*t
10=(r-3)t (against the current)
10=(r+3)(3.5-t) (with the current)
10/(r-3)=t from the first equation
substitute this into the second equation
10=(r+3)(3.5-[10/[r-3])
multiply both sides by (r-3)
10(r-3)=(r+3)(r-3)(3.5-[10/(r-3)])
10(r-3)=(r+3)[(3.5)(r-3)-10]
10(r-3)=(r+3)(3.5r-10.5-10)
10(r-3)=(r+3)(3.5r-20.5)
10r-30=3.5r2+10.5r-20.5r-61.5
10r-30=3.5r2-10r-61.5
3.5r2-10r-61.5-10r+30=0 (get all terms on one side)
3.5r2-20r-31.5=0
multiply both sides by 2 to eliminate the decimals
7r2-40r-63=0
7*63=7*7*9 and (7*7)-9=40, the coefficient of the middle term
(7r+9)(r-7)=0
r-7=0
r=7 mph is Bryn's rate
check: 10=(7-3)t, 10=4t, t=2.5 hours upstream
10=(7+3)(3.5-2.5)
10=10(1), t=1 hour downstream