Alison K.

asked • 11/16/14

Having trouble calculating concave up and concave down?

Here is the question I am having trouble withL
Calculate the second derivative of f. Find where f is concave up, concave down, and has inflection points. f(x)= (3x^2) / (x^2 + 49)?
I figured out the second derivative.
f"(x) = -(294 (3x^2 - 49)) / (x^2 +49)^3
and that the Inflection points are:
x = -4 and 4
However on what intervals are the Concave up and Concave down located? Thank you!

2 Answers By Expert Tutors


Byron S. answered • 11/16/14

5.0 (44)

Math and Science Tutor with an Engineering Background

Dal J. answered • 11/16/14

4.9 (64)

Expert Instructor in Complex Subjects and Public Speaking

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