Byron S. answered 11/14/14
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f(x) = x + 1/x
This function has a discontinuity at x = 0.
limx->0+ x+1/x = +∞
There is no absolute/global maximum value.
f'(x) = 1 - 1/x2
f'(x) = 0 when x = ±1. We ignore negatives, so x=1.
f''(x) = 1/x3
f is concave up for all positive x. Therefore, x=1 is a minimum.
f(1) = 1 + 1/1 = 2 is the minimum value for x>0.