Molarity of vinegar

Question

Hello

I am trying to work out the molarity of a standard store bought vinegar.
i used 2g sodium hydroxide in 0.1M in 500ml.
10ml vinegar diluted with 90g water.
25 ml of vinegar solution used in tritration.
result was 20.3 ml

How do i work out the molarity of the vinegar from these results?

here are my equations so far, im not so sure im correct :/

Volume of NAOH aqueous = 20.3ml
Concentration of NAOH =   0.1 M
Volume of vinegar aqueous = 25ml

N(NAOH) = C(NAOH) x v(NAOH) = 0.1 x 20.3 = 2.03
C (Vinegar) = N(Vinegar) / V(Vinegar) = 2.03 / 25 = 0.08

Answer 1

Stephen,

 

You are on the right track and your calculations so far are correct.

 

 

Then, use the expression 

 

C₁V₁= C₂V₂

 

You know V1, C2, and V2.  Calculate for C1.