What is the energy change when the temperature of 14.2 grams of solid titanium is decreased from 37.9 °C to 21.7 °C ?

Question

Answer must be in Joules.

Answer 1

q = m c ΔT

where q = heat absorbed or released

m = mass = 14.2 g

c = specific heat = 0.544 g / J °C

ΔT = T_f - T_i = 21.7 - 37.9 = -16.2 °C

q = 14.2 g x 0.544 g / J °C x -16.2 °C = –125 J