How much energy is required to raise the temperature of 10.5 grams of solid iron from 20.3 °C to 38.9 °C ?

Question

Answer must be in Joules.

Answer 1

q = m c ΔT

where q = heat absorbed or released

m = mass = 10.5 g

c = specific heat = 0.450 g / J °C

ΔT = T_f - T_i = 38.9 - 20.3 = 18.6 °C

q = 10.5 g x 0.450 g / J °C x 18.6 °C = 87.9 J