A volume of 40.0 mL of a 0.860 M HNO3 solution is titrated with 0.570 M KOH. Calculate the volume of KOH required to reach the equivalence point.

Answer 1

The balanced chemical reaction is:

HNO₃ + KOH → KNO₃ + H₂O

1) Calculate moles of HNO₃ using its molarity and volume.

mol HNO₃ = 0.860 mol/L x 40.0 mL x 1 L/1000 mL = 0.0344 mol HNO₃

2) Convert mol HNO₃ to mol KOH using the mole ratio from the balanced reaction, which is 1:1.

mol KOH = 0.0344 mol HNO₃ x 1 mol KOH / 1 mol HNO₃ = 0.0344 mol KOH

3) Calculate volume of KOH using moles KOH and Molarity (0.570 M)

V_KOH = 0.0344 mol KOH x (1 L / 0.570 mol) x (1000 mL / 1 L) = 60.4 mL