
Francisco P. answered 11/07/14
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Rigorous Physics Tutoring
1 mole NaOH = 39.997 grams
1 mole Na2SO4 = 142.042 grams
For every 2 moles of NaOH reacted, 1 mole of Na2SO4 is produced.
200 grams NaOH x (1 mole NaOH / 39.997 g NaOH) x (1 mole Na2SO4 / 2 moles NaOH) x (142.042 g Na2SO4 / 1 mole Na2SO4) = 355 grams.