y is the larger and y-2 is the smaller.

4y + (y-2)^{2} = 49

4y + y^{2} - 4y + 4 = 49

y^{2} = 45

y - 3√5 and x = 3√5√ -2

Amy R.

asked • 02/20/19A positive real number is 2 less than another. When 4 times the larger is added to the square of the smaller, the result is 49. Find the numbers.

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y is the larger and y-2 is the smaller.

4y + (y-2)^{2} = 49

4y + y^{2} - 4y + 4 = 49

y^{2} = 45

y - 3√5 and x = 3√5√ -2

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Amy R.

Thank you so much!02/20/19