How to find how much calcium phosphate was actually obtained through experiment

Question

3 CaCO3 + 2 FePO4 -> Ca3(PO4)2 + Fe2(CO3)2 is the formula

If the percent yield ends up being 95%, and you began with 0.40 moles of calcium carbonate, how much calcium phosphate was actually obtained through experiment?

Answer 1

Look at the molar ratios in the chemical reaction equation. For every 3 moles of calcium carbonate there is 1 mole of calcium phosphate created. That means for every 0.4 moles of calcium carbonate, there would be 0.40/3 moles of calcium phosphate created. But since you only had a 95% efficiency, only 0.95(0.40/3) moles was created.