Dimensional Analysis in a problem

Question

The density of aluminum is 2.70g/cm^3. A square piece of aluminum foil, 22.86 cm on a side, is found to weight 2.568 g.

What is the thickness of the foil, in millimeters?

Answer 1

The total volume of the foil can be found by dividing the mass by the density:

(2.568g) / (2.70 g/cm³) = 0.9511 cm³

If volume = length x width x thickness, then

thickness = volume / (length x width) = 0.9511 cm³ / (22.86 cm x 22.86 cm) = 0.001820 cm = 1.820 mm