30 more tickets were sold at the door then in advance and $2630 were collected. How many tickets were sold at the door?

Question

Please help me with the best answer and how to do it 

MORE INFORMATION: the advance tickets cost $3 and the door tickets cost $5 

Answer 1

Let x = the number of tickets in advance

And x+30= the number of tickets sold at the door.

 

The equation becomes

 

3x+5(x+30)=2630

3x+5x+150=2630

 

8x+150=2630

    -150   -150

 

8x=2480

 

x=310

Thus 310+30=340 Tickets sold at the door.

Answer 2

Let D equal to the number of tickets sold at the door.

 

Let A equal to the number of tickets sold in advance.

 

30 more tickets were sold at the door than in advance.

D = A + 30

 

Door Tickets = $5 each
Advance Tickets = $3 each

Total amount collected: $2630

 

2630 = 5D + 3A

2630 = 5(A + 30) + 3A

2630 = 5A + 150 + 3A

2630 - 150 = 5A + 3A

2480 = 8A

310 = A

 

310 tickets were sold in advance

 

D = A + 30

D = 310 + 30

D = 340

 

340 tickets were sold at the door