There are two large numbers whose sum is 64.The larger number subtracted from four times the smaller number gives 31 what are the two. Numbers

Answer 1

Whenever you have this type of question, you have to figure out math terms for the words in the question.

Let's call our numbers a and b.

The first sentence tells us that a + b = 64

The larger number: b

Subtracted from four times the smaller number: 4a -

4a - b = 31

Since you cannot solve an equation with two variables (letters) we'll use the first equation to find a different name for a.

a + b = 64. If we subtract b from both sides: a = 64 - b

Now we can plug in 64 - b instead of a in the second equation: 4(64-b) - b = 31

Distribute the 4: 256 - 4b - b = 31

Combine like terms: 256 - 5b = 31

Subtract 256 from both sides: -5b = -225

Divide both sides by -5: b = 45

Now plug 45 into the first equation instead of b: a + 45 = 64

Subtract 45 from both sides: a = 19

So your two numbers are 19 and 45.