Air trapped in a cylinder fitted with a piston occupies 120.8 mL at 1.08 atm pressure. What is the new volume when the piston increased 25%

Answer 1

P₁V₁ = P₂V₂

P₁ = 1.08 atm

V₁ = 120.8 mL

P₂ = 1.08 + (1.08 x 25%) = 1.08 + 0.27 = 1.35 atm

Solve for V₂

V₂ = P₁V₁ / P₂ = (1.08 atm x 120.8 mL) / 1.35 atm = 96.64 mL