This is a complicated question which I will not try to answer completely for you but I will get you started.
There are 6C3 = 20 ways to pick the seats for the husbands and they can be arranged in those 3 seats in 6 ways, then the wives can be placed in the 3 remaining seats in 6 ways. That means there are 720 possible outcomes; this will be the denominator in your calculation of probability.
Now comes the hard part. Make some pictures to get at what you are trying to accomplish.
For example:
mmm, there are 6 permutations, 2 with husband A on the right end, 2 with husband B and with husband C and with each arrangement there are 4 ways to fill the remaining seats so that Hx and Wx do not sit next to each other, i.e. 24 ways in which 3 men occupy the end seats with no wife next to her husband.
Now you have to do the same kind of analysis for wmmm and then for all the rest of the possible arrangements ...and that is quite a counting job. It can be done but will take persistence!
For each arrangement of the men there are 6 permutations and each of those permutations will require a different thought process about seating the wives.
The only way I can think of to make it something like do-able is to make a spreadsheet showing the 20 possible ways the men can be seated and then for each arrangement figure out what to do with the wives
Good luck!
P.S. Your English grammar needs help also, Subject and predicate must agree in number. A sentence ends with a period and a question begins with a capital letter. The English language is a beautiful precision tool which you should learn to use accurately!
