Lauren H. answered • 01/30/19
7 years experience teaching High School Chemistry and Honors Chemistry
A brief examination of your equation shows that it is not balanced. You show 6 H on the reactant side and 8 H on the product side. Likewise, your O atoms are unbalanced. Please rebalance equation and reply so we can go forward.
Lauren H.
You need help balancing equations. You have 4 C on the left and 12 C on the right.01/30/19
Lauren H.
Oh no. It's correct. Let me reduce it:2C3H6 + 9CO2 yields 6 CO2 + 6 H2). Can you do the problem from here?01/30/19
Lauren H.
84 g C3H6 x (1 mol C3H6/42.08 g C3H6) x (9 mol CO2/2 mol C3H6) = solve this in mols of CO2.01/30/19
Lauren H.
128 g O2 x (1 mol O2/32 g O2) x (6 mol CO2/ 9 mol O2) = solve01/30/19
Lauren H.
Sorry, error in mol ratio above, should be 6 mol CO2. Having trouble working in this little box.01/30/19
Lauren H.
Lesser amount of mole of CO2 result indicates the LR. Use LR to solve for g of CO2.01/30/19
Taylor A.
Sorry, what is LR?01/30/19
Lauren H.
Limiting reactant01/30/19
Taylor A.
My balanced equation is: 4C3H6 + 18O2 = 12CO2 12H2001/30/19