Philip P. answered 11/04/14
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Let b = the mass of a box and c = the mass of a cube
Box A contains 53 cubes and has a mass of 1760 grams: 53c + b = 1760
Box B contains 18 cubes and has a mass of 1620 grams: 10c + b = 1620, so b = 1620 - 10c
Since b = 1620 - 10c, let's substitute 1620 - 10c in place of b in teh seond equation and solve for c:
53c + b = 1760
53c + 1620 - 10c = 1760
43c = 140
c = 3.256 grams
Now we can solve for b:
b = 1620 - 10c
b = 1620 - 32.56
b = 1587.44 grams
Check:
53c + b = 1760
53(3.256) + 1587.44 = 1760
1760.08 = 1760 [Checks within rounding error]
10c + b = 1620
10(3.256) + 1587.44 = 1620
32.56 + 1587.44 = 1620
1620 = 1620 [Checks]
David W.
11/04/14