
Amarjeet K. answered 11/04/14
Tutor
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Professional Engineer for Math and Science Turoring
Force required to keep thge car from from sliding down is the component of weight of the car acting along the hill surface
M= mass of car = 3700 pounds
g = acceleration due to gravity = 32 ft/s2
Θ = angle of the hill surface with horizontal
Wt of car = Mg
component of the wt acting along with the surface of hill = MgsinΘ = force required up the hill along hill surface assumiing a frictionless hill surface.
If hill surface has a coefficient of friction μ
Friction force acting to oppose downward motion of the car = μR(reaction of the hill surface on car due to perpendicular component of wt acting on the hill surface)= μMgcosΘ
Therefore Force required to keep the car from sliding down = MgsinΘ - μMgcosΘ
:)