Let x = 1st number and x+1 = 2nd number, then
(x/2)+[(x+1)/3]=22
Clear fractions (multiply by 6)
3x + 2(x+1) = 132
5x +2 = 132
5x=130
x=26, and x+1=27
Nikko Jay H.
asked 01/21/19Let x = 1st number and x+1 = 2nd number, then
(x/2)+[(x+1)/3]=22
Clear fractions (multiply by 6)
3x + 2(x+1) = 132
5x +2 = 132
5x=130
x=26, and x+1=27
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