Find two consecutive odd integers whose product is 1599

Answer 1

find two consecutive odd integers whose product is 1599

Two consecutive odd numbers are separated by 1 (ie.3,5,7, 9)

(x-1) (x+1) = 1599

X^{2 –} 1 = 1599

X²  - 1 + 1 = 1599 + 1

X^{2 =} 1600

X = 40

40 – 1  =    39

40 + 1     =  41

Answer 2

Two consecutive odd integers are 2 apart (1, 3, 5, 7, etc.) So if one integer is x, the other one is x+2.

Their product is 1599. So, x(x+2) = 1599.

x^2 + 2x = 1599

x=39 x+2 = 41. 39 x 41 = 1599