
Patrick B. answered 01/12/19
Math and computer tutor/teacher
I = k/d^2 for some fixed constant k
9 = k/4^2 = k/16 ---> k = 9*16 = 144
So the function is I = 144/d^2
for d=6, I = 144/6^2 = 144/36 = 4
Dave O.
asked 01/12/19The intensity of illumination (I) of a light source varies inversely as the square of the distance (d) from the source. If the Illumination 4 ft from the source is 9 foot candles (fc), find the illumination 6 ft from the source.
Patrick B. answered 01/12/19
Math and computer tutor/teacher
I = k/d^2 for some fixed constant k
9 = k/4^2 = k/16 ---> k = 9*16 = 144
So the function is I = 144/d^2
for d=6, I = 144/6^2 = 144/36 = 4
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Dave O.
Thanks01/14/19