Tiffany W. answered 01/09/19
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The first step is to balance the equation. Ca(OH)2 + 2 HCl →CaCl2 + 2 H2O, is in the balanced form.
The next step is to calculate the molecular weight. CaCl2 contains one calcium and two chlorine atoms, which exhibit atomic weights of 40.08 and 35.45, respectively. The molecular weight of CaCl2 is therefore (1 x 40.08) + (2 x 35.45) = 100.98.
Theoretical Yield is the amount of product that would have been produced if all of the limiting reagent reacted and it was 100% pure. The limiting reagent is used up first in a reaction and controls the amount of product that can be produced.
Therefore, we will use straight mass-mass stoichiometry problem from the limiting reagent.
Mass CaCl2 = 0.8 mol Ca(OH)2 x (1 mol CaCl2 / 1 mol Ca(OH)2) x (110.98g CaCl2 / 1 mol CaCl2) = 88.78 g CaCl2