
Russ P. answered 10/30/14
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Krisli,
The general quadratic polynomial equation is ax2 + bx + c = 0, so a=2, b=11, and c=-51.
And the general solution is x = [-b ±√(b2 - 4ac)]/2a, substituting in your values
b2 - 4ac = (121) - 4(2)(-51) = 121 + 408 = 529, and the square root of 529 is 23.
So x1 = [-11 + 23]/4 = 12/4 = +3 is one solution
and x2 = [-11 - 23]/4 = -34/4 = - 17/2 is the other solution.

Russ P.
10/30/14