Xavier J. | Tutor in Math, topics range from Algebra to Calculus.Tutor in Math, topics range from Algebra...

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I am assuming the first equation is the parabola y = x^{2 }- 3. To graph a parabola I always recommend starting with the vertex and then plotting at least 2 other points.

One way to find the vertex is to put your equation in the form y = (x - k)^{2
}+ h where the vertex is the point (k,h). We see that this can done easily by simply by saying y = (x - 0)^{2
}- 3. This gives us that the vertex is at the point (0,-3). Now that the vertex is known choose two other x values (one on each side of the vertex) plot those points by plugging them into the equation and that should be enough to get a rough sketch of the parabola.

Next we must graph the linear equation y = 2x. For any linear equation we always start with y - intercept and from the there since the slope is 2, we go up 2 and over to the right 1 to get the next point (repeat again for a 3rd point if you would like).

Finally once both graphs are sketched, the solutions to the equation x^{2} - 3 = 2x will be the x values where they intersect.