How to calculate the number of moles of barium chloride that will be produced by the reaction of 257 g of barium hydroxide and 94 g of hydrochloric acid? The equation must be written out and balanced.

Answer 1

First you need to write out the equation

Ba(OH)2 + 2 HCl → BaCl2 + 2 H2O.

then you need to convert g of Ba(OH)2 to moles ...

Do the same for the HCL

Then for every mole of Ba(OH2) - you produce one mole of BaCl2 - so you can figure out how many moles of BaCl2 you have. Then convret moles of that back to grams.

If you are doing limiting reagents - you have to repeat this for the Hcl - only this time for every TWO moles of HCl you product ONE mole of BaCl2. So you find the max number of moles (and therefore grams) of BaCl2 that could be produced.

Whichever is lower -is the answer because the equation is limited by that reagent.