Cara Marie M. answered • 12/27/18
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100 g NH3 * (1 mol NH3 / 17 g NH3) * (5 mol N2 / 4 mol NH3) * (28 g N2 / 1 mol N2) = 205.9 g
The first step converts grams of NH3 to moles of NH3 using the periodic table. The second step uses the mole to mole ratio in the equation and the 3rd step converts moles of N2 to grams of N2 using the periodic table.
J.R. S.
tutor
In this problem since they don’t tell you how much NO is present so you must assume it is present in excess. It’s actually a poorly written question. Also note that the answer given has 4 sig figs but should be rounded to 206 g with 3 sig figs.
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12/27/18
Cara Marie M.
tutor
Agreed, it is a poorly worded question. When I wrote it out, I assumed that the NO was in excess and therefore, we wouldn't have to calculate for a limiting reagent.
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01/10/19
Mir B.
Thank you! When we were taught how to do this equation, we were told to use substance a and substance b when plugging the information into the equation. Therefore, at first I did NH and NO. So why here do you do NH and N?12/27/18