The sum of three consecutive natural numbers is by 213 greater than twice the smallest of them. Please find the smallest of the three numbers!

Answer 1

n, n+1, n+2 are the numbers

n+n+1+n+2=213+2n

3n+3=213+2n

3n-2n=213-3

n=210 is the smallest

check:210+211+212=213+2(210)

633=213+420

633=633