
Mark M. answered 12/24/18
Mathematics Teacher - NCLB Highly Qualified
f(x) = a(x - 5)(x - 3)(x + i)(x - 1)(x - 1 - i)(x + 1 + i)
To determine a, substitute 0 for x and 88 for f(0) and solve for a.
Anas C.
asked 12/24/18Find an equation for f(x) , the polynomial of smallest degree with real coefficients such that f(x) breaks through the x-axis at 5 , breaks through the x-axis at 3 , has complex roots of -1-i and -i and passes through the point(0,88) .
Mark M. answered 12/24/18
Mathematics Teacher - NCLB Highly Qualified
f(x) = a(x - 5)(x - 3)(x + i)(x - 1)(x - 1 - i)(x + 1 + i)
To determine a, substitute 0 for x and 88 for f(0) and solve for a.
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