calculate the frequency and energy for a wavelength of .0618 m of the visible light spectrum

Answer 1

c = λν

3 x 10^8 m/s = (.0618m)(ν)

ν = 48.54 x 10^8 Hertz

ν = 4.85 x 10^9 Hertz

Hertz is sec^-1, or, per second

E = hν

E = (6.63 x 10^-34 J sec)(4.85 x 10^9 sec^-1)

E = 32.16 x 10^-25 J

E = 3.22 x 10^-24 J