titration calculation

Question

1. Write the formula to be used in calculation of the concentration of acid and name each term of the formula.

HCl (l)  +  NaOH (l) →NaCl (aq) + H2O (l)

V2 = 20 mL        V1= 25.50 mL

     =0.02 L              = 0.0255 L

c1 = ?              c1= 1.0 M

3.Calculate the concentration of the HCl used in the procedure.

4.Calculate the theoretical volume of 1 M NaOH to be required to titrate 10 mL of 2M HCl.

Answer 1

Hello Aellie. In order to solve this equation, you must remember the molarity formula. m1v1=m2v2, where the letter m represents molarity (moles/liter) or concentration, and the letter v represents the volume (in liters). Then you substitute the values for M1, V1. and V2. These are the values you have for M1, V1, and V2:

HCl NaOH

V2 = 20 mL        V1= 25.50 mL

     =0.02 L              = 0.0255 L

m2 or c1 = ?             m1 or c1= 1.0 M

The formula then becomes:

M1V1=M2V2

(1.0 M NaOH)(0.0255 L NaOH) = (x)(0.02 L HCl)

Rearranging the equation to solve for x gives us:

(1.0 M NaOH)(0.0255 L NaOH)= x

(0.02 L HCl)

x= 1.275 M HCl, or reduced to 2 significant figures, 1.3 M HCl

For the second problem, you set up the same formula:

M1V1=M2V2

You then proceed to convert 10 ml into liters. 10 ml HCl is equivalent to 0.01 L HCl.

You then substitute the given values into the equation:

M1V1=M2V2

(1 M NaOH)(x) = (2 M HCl)(0.01 L HCl)

Rearranging the equation to solve for x gives us:

x = (2 M HCl) (0.01 L HCl)

(1 M NaOH)

x = 0.02 L NaOH or 20 ml of NaOH