find the inverse of 4x^3-1

Answer 1

Read this:

http://www.coolmath.com/algebra/16-inverse-functions/05-how-to-find-the-inverse-of-a-function-01

I assume you mean:

y = 4x^3 - 1

So,

x = 4y^3 - 1

Solve for y:

x + 1 = 4y^3

(x + 1)/4 = y^3

cube root of [(x + 1)/4] = y