C = cost of chairs, T = cost of tables.
5C + 2T = 26
3C + 8T = 87
To solve this set, multiply the first equation by 4 then subtract the 2nd equation from the multtiplied 1st equation. You solve it from there.
Melina M.
asked 12/14/18A party rental company has chairs and tables for rent. The total cost to rent 5 chairs and 2 tables is 26. The total cost to rent 3 chairs and 8 tables is 87 . What is the cost to rent each chair and each table?
C = cost of chairs, T = cost of tables.
5C + 2T = 26
3C + 8T = 87
To solve this set, multiply the first equation by 4 then subtract the 2nd equation from the multtiplied 1st equation. You solve it from there.
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