At a temperature of 47 ° C, the size of any mass mass 640cm and pressure 75 cmHg When the heat is used without any change in the volume, which temperature will double the temperature of the gas?

Question

At a temperature of 47 ° C, the size of any mass mass 640cm and pressure 75 cmHg When the heat is used without any change in the volume, which temperature will double the temperature of the gas?

Answer 1

Your question makes no sense. It asks which temperature will double the temperature of the gas. You probably meant to ask what temperature will double the PRESSURE of the gas when there is no change in volume. If you look at the combined gas law, you see that P1V1/T1 = P2V2/T2 and since volume is constant, this reduces to P1/T1 = P2/T2. If P2 is twice P1 (ie you doubled the pressure), then you can solve P2 in terms of P1. Thus ...

P1/T1 = 2P1/T2 and solving for T2 you find T2 = 2T1. This means you need to double the temperature to double the pressure when the volume is constant. In performing calculations dealing with gases, we use temperature in Kelvin, so we convert 47ºC to K by adding 273 = 320 K. Thus, doubling this we get 640 K as our answer. Converting back to Celsius, we obtain 640 - 273 = 367ºC.