First, find the theo yield of ethanol from the stoichiometric equation as follows:
(46.0 g ethanol/1 mol ethanol) (4 mol ethanol/1 mol sucrose) (1 mol sucrose/342.2 g sucrose) 680. g sucrose
= 365.6 g ethanol. This is the theoretical yield
% Yiels = (actual yield/theo yield) x 100 = (305.5 g/365.6 g) x 100 = 83.0 %