mixing 9% and 15% acid solution gives 300ml of a 10% acid solution.How much of each acid solution must be used

Answer 1

x = ml of 9%

300 - x = ml of 15%

(x)(9%) + (300-x)(15%) = (300)(10%)

9x + 4500 - 15x = 3000

-6x = -1500

x = 250 mls of 9%

300 - 250 = 50 mls of 15%