URGENT !!!!!!!! PROBABILITY; MATHEMATICS

Question

There are 29% students who love to read magazines including 17% who dislike novels. 3% of students doesn't like to read both. Event A,B,C are as followed;

A: students who likes to read magazines

B: students likes to read novels

C: students like to read magazines or novel but not both

Find the probability of:

1. P(A)
2. P(B)
3. (B l A)
4. P(B∩C)

Answer 1

helps to sketch a Venn diagram, a rectangle with 2 over lapping circles inside. 3% don't like mags or novels.

1) P(A) = 29% = .29 = 29/100

2) P(B) = .85 = 85% = 85/100= 17/20

3) P(B/A) = .12/.17 = 12/17

4) P(B intersection C) = .29-.12= .17= 17/100

P(AUB) = .1-.03 = .97 = 97/100

P(B/A)P(A) = P(A/B)P(B) is Bayes Theorem, rearranged dividing by P(A) is:

P(B/A) = P(B/A)P(A)/P(B) = (12/17)(29/100)/(17/20) = (12/17)(29/100)(20/17) = 344/1445 which is Not 12/17, error(s) somewhere above. generally Venn diagram numbers are far less error prone than Bayesian calculations