Whiz S. answered • 12/06/18

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p(t)= Pe^{0.03t}

Charles R.

asked • 12/06/18Suppose that ap is invested in a savings account in which interest k is coumpounded continuously at 3% per year. The balance P(t) after time t, in years, is P(t) is P(t)=Pe^{KT }

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Whiz S. answered • 12/06/18

Tutor

New to Wyzant
Experienced and patient Math tutor

p(t)= Pe^{0.03t}

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