What mass of calcium nitrate is required to make 400.0ml of a 0.250 M solution
Lauren H.
answered 11/11/18
7 years experience teaching High School Chemistry and Honors Chemistry
Ca(NO3)2
(0.250mol/L) x .4L x (164.09 g Ca(NO3)2/ 1 mol Ca(NO3)2) = ?
Multiply to get answer
Still looking for help? Get the right answer, fast.
OR
Find an Online Tutor Now
Choose an expert and meet online.
No packages or subscriptions, pay only for the time you need.