Mai, Trey, and Dan served a total of 128 orders Monday at the school cafeteria. Mai served 10 more orders than Trey. Dan served 4 times as many orders as Mai. How many orders did they each serve?

Answer 1

M = Mai, T = Trey and D = Dan

Eq 1: M + T + D = 128

Eq 2: M = 10 + T

Eq 3: D = 4M

Substitute Eq 2 into 3, you get

D = 4(10 +T) = 40 + 4T --> Substitute this equation and Eq 2 into 1, you get

10 + T + T + 40 + 4T = 128

6T + 50 = 128

6T = 78

T = 78 / 6 = 13

Substitute T = 13 into Eq 2

M = 10 + T = 10 + 13 = 23

Substitute M = 23 into Eq 3

D = 4M = 4(23) = 92