Chemistry help i am not understanding

Question

What is the volume in L of 0.0589 mole of gas at 722 torr and 37 C?

Answer 1

Use the ideal gas law equation to solve this problem.

PV = nRT

rearrange to solve for V

V = nRT / P

n = # of moles = 0.0589 mol

P = pressure = 722 torr --> need to convert to units of atm by using the conversion factor, 1 atm = 760 torr

P in atm = 722 torr x (1 atm / 760 torr) = 0.950 atm

R = Gas constant = 0.0821 L atm mol^-1 K^-1

T = Temperature = 37 °C --> need to convert to Kelvin = 37 °C + 273 K = 310 K

Solve for V

V = (0.0589 mol x 0.0821 L atm mol^-1 K^-1 x 310 K) / 0.950 atm = 1.58 L