Mark M. answered 11/30/18
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
∫[(2x)(3x2)dx = ∫(6x3)dx = 6(x4/4) + C = (3/2)x4 + C
∫(2x)dx ∫(3x2)dx = (x2)(x3) + C = x5 + C