Patrick B. answered 11/28/18
Math and computer tutor/teacher
X+Y+Z = 120000
Y = Z+10000
0.022X + 0.06y - 0.02Z = 2820
X+(Z+10000) + Z = 120000
0.022X + 0.06(Z+10000) - 0.02Z = 2820
X + 2Z = 110000
0.022X + 0.06Z + 600 - 0.02Z = 2820
0.022(110000 - 2Z) + 0.06Z + 600 - 0.02Z = 2820
2420 - 0.044Z + 0.06Z + 600 - 0.02Z = 2820
3020 - -0.004z = 2820
0.004z = 200
z=50000
y=60000
x=10000