
Patrick B. answered 11/24/18
Math and computer tutor/teacher
Then 3-2i must be a zero.
The polynomial for these factors are (x-3)+2i and (x-3)-2i
Multiplying them: [(x-3) + 2i ][ (x-3) - 2i ]
= (x-3)^2 - (-4)
x^2 - 6x + 13
Next divides this polynomial into the original polynomial function. THe result shall be quadratic
x^2- 2x + 14
divides x^2 - 6x + 13 | x^4 - 8x^3 + 26x^2 - 32x + 13
x^4 - 6x^3
-----------------------------------------
-2x^3 + 26x^2
-2x^3 + 12x^2
------------------------
14x^2 - 32x
14x^2 - 84x
----------------
52x + 13
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